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2/5x+10+3/5=2x+5
We move all terms to the left:
2/5x+10+3/5-(2x+5)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
2/5x-2x-5+10+3/5=0
We calculate fractions
-2x-5+10=0
We add all the numbers together, and all the variables
-2x+5=0
We move all terms containing x to the left, all other terms to the right
-2x=-5
x=-5/-2
x=2+1/2
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