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2/5x+16=14-3/10x
We move all terms to the left:
2/5x+16-(14-3/10x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/5x-(-3/10x+14)+16=0
We get rid of parentheses
2/5x+3/10x-14+16=0
We calculate fractions
20x/50x^2+15x/50x^2-14+16=0
We add all the numbers together, and all the variables
20x/50x^2+15x/50x^2+2=0
We multiply all the terms by the denominator
20x+15x+2*50x^2=0
We add all the numbers together, and all the variables
35x+2*50x^2=0
Wy multiply elements
100x^2+35x=0
a = 100; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·100·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*100}=\frac{-70}{200} =-7/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*100}=\frac{0}{200} =0 $
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