2/5x+1=1/2x-3

Solution for 2/5x+1=1/2x-3 equation:

2/5x+1=1/2x-3

We move all terms to the left:

2/5x+1-(1/2x-3)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 2x-3)!=0

x∈R


We get rid of parentheses

2/5x-1/2x+3+1=0

We calculate fractions


4x/10x^2+(-5x)/10x^2+3+1=0

We add all the numbers together, and all the variables

4x/10x^2+(-5x)/10x^2+4=0

We multiply all the terms by the denominator


4x+(-5x)+4*10x^2=0

Wy multiply elements

40x^2+4x+(-5x)=0

We get rid of parentheses

40x^2+4x-5x=0

We add all the numbers together, and all the variables

40x^2-1x=0

a = 40; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·40·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*40}=\frac{0}{80}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*40}=\frac{2}{80}
=1/40
$