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2/5x+1=1/3+x
We move all terms to the left:
2/5x+1-(1/3+x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-3
x!=-3/1
x!=-3
x∈R
2/5x-(+x+1/3)+1=0
We get rid of parentheses
2/5x-x+1-1/3=0
We calculate fractions
There is no solution for this equation
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