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2/5x+1=4/5
We move all terms to the left:
2/5x+1-(4/5)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/5x+1-(+4/5)=0
We get rid of parentheses
2/5x+1-4/5=0
We calculate fractions
1!=0
There is no solution for this equation
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