2/5x+21=-1/5(8x-25-2x

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Solution for 2/5x+21=-1/5(8x-25-2x equation: 



2/5x+21=-1/5(8x-25-2x

We move all terms to the left:

2/5x+21-(-1/5(8x-25-2x)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 5(8x-25-2x)+21!=0

We move all terms containing x to the left, all other terms to the right

5(8x-25-2x)!=-21

x∈R



We add all the numbers together, and all the variables

2/5x-(-1/5(6x-25)+21=0

We calculate fractions


(10x(6+21)/(25x^2(6+21)+(-(-1*5x)/(25x^2(6+21)=0



We calculate terms in parentheses: +(10x(6+21)/(25x^2(6+21)+(-(-1*5x)/(25x^2(6+21), so:

10x(6+21)/(25x^2(6+21)+(-(-1*5x)/(25x^2(6+21

We can not solve this equation

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