2/5x+2=1/4x+7

Solution for 2/5x+2=1/4x+7 equation:

2/5x+2=1/4x+7

We move all terms to the left:

2/5x+2-(1/4x+7)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 4x+7)!=0

x∈R


We get rid of parentheses

2/5x-1/4x-7+2=0

We calculate fractions


8x/20x^2+(-5x)/20x^2-7+2=0

We add all the numbers together, and all the variables

8x/20x^2+(-5x)/20x^2-5=0

We multiply all the terms by the denominator


8x+(-5x)-5*20x^2=0

Wy multiply elements

-100x^2+8x+(-5x)=0

We get rid of parentheses

-100x^2+8x-5x=0

We add all the numbers together, and all the variables

-100x^2+3x=0

a = -100; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-100)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-100}=\frac{-6}{-200}
=3/100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-100}=\frac{0}{-200}
=0
$