2/5x+3/5x+x+30=360

Solution for 2/5x+3/5x+x+30=360 equation:

2/5x+3/5x+x+30=360

We move all terms to the left:

2/5x+3/5x+x+30-(360)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

x+2/5x+3/5x-330=0

We multiply all the terms by the denominator


x*5x-330*5x+2+3=0

We add all the numbers together, and all the variables

x*5x-330*5x+5=0

Wy multiply elements

5x^2-1650x+5=0

a = 5; b = -1650; c = +5;
Δ = b2-4ac
Δ = -16502-4·5·5
Δ = 2722400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2722400}=\sqrt{400*6806}=\sqrt{400}*\sqrt{6806}=20\sqrt{6806}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1650)-20\sqrt{6806}}{2*5}=\frac{1650-20\sqrt{6806}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1650)+20\sqrt{6806}}{2*5}=\frac{1650+20\sqrt{6806}}{10}
$