2/5x+32=27

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Solution for 2/5x+32=27 equation: 



2/5x+32=27

We move all terms to the left:

2/5x+32-(27)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We add all the numbers together, and all the variables

2/5x+5=0

We multiply all the terms by the denominator


5*5x+2=0

Wy multiply elements

25x+2=0

We move all terms containing x to the left, all other terms to the right

25x=-2

x=-2/25

x=-2/25

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