2/5x+3=4(7/8+1x/12)

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Solution for 2/5x+3=4(7/8+1x/12) equation:


x in (-oo:+oo)

(2/5)*x+3 = 4*((1*x)/12+7/8) // - 4*((1*x)/12+7/8)

(2/5)*x-(4*((1*x)/12+7/8))+3 = 0

(2/5)*x-4*(x/12+7/8)+3 = 0

(2*x)/5-4*(1/12*x+7/8)+3 = 0

(-4*5*(1/12*x+7/8))/5+(2*x)/5+(3*5)/5 = 0

2*x-4*5*(1/12*x+7/8)+3*5 = 0

1/3*x-35/2+15 = 0

1/3*x-5/2 = 0

(1/3*x-5/2)/5 = 0

(1/3*x-5/2)/5 = 0 // * 5

1/3*x-5/2 = 0

1/3*x-5/2 = 0 // + 5/2

1/3*x = 5/2 // : 1/3

x = 5/2/1/3

x = 15/2

x = 15/2

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