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2/5x+4=3x-9
We move all terms to the left:
2/5x+4-(3x-9)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
2/5x-3x+9+4=0
We multiply all the terms by the denominator
-3x*5x+9*5x+4*5x+2=0
Wy multiply elements
-15x^2+45x+20x+2=0
We add all the numbers together, and all the variables
-15x^2+65x+2=0
a = -15; b = 65; c = +2;
Δ = b2-4ac
Δ = 652-4·(-15)·2
Δ = 4345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-\sqrt{4345}}{2*-15}=\frac{-65-\sqrt{4345}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+\sqrt{4345}}{2*-15}=\frac{-65+\sqrt{4345}}{-30} $
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