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2/5x+5=-2/6x+1
We move all terms to the left:
2/5x+5-(-2/6x+1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 6x+1)!=0We get rid of parentheses
x∈R
2/5x+2/6x-1+5=0
We calculate fractions
12x/30x^2+10x/30x^2-1+5=0
We add all the numbers together, and all the variables
12x/30x^2+10x/30x^2+4=0
We multiply all the terms by the denominator
12x+10x+4*30x^2=0
We add all the numbers together, and all the variables
22x+4*30x^2=0
Wy multiply elements
120x^2+22x=0
a = 120; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·120·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*120}=\frac{-44}{240} =-11/60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*120}=\frac{0}{240} =0 $
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