2/5x+5=1/2x-7

Solution for 2/5x+5=1/2x-7 equation:

2/5x+5=1/2x-7

We move all terms to the left:

2/5x+5-(1/2x-7)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 2x-7)!=0

x∈R


We get rid of parentheses

2/5x-1/2x+7+5=0

We calculate fractions


4x/10x^2+(-5x)/10x^2+7+5=0

We add all the numbers together, and all the variables

4x/10x^2+(-5x)/10x^2+12=0

We multiply all the terms by the denominator


4x+(-5x)+12*10x^2=0

Wy multiply elements

120x^2+4x+(-5x)=0

We get rid of parentheses

120x^2+4x-5x=0

We add all the numbers together, and all the variables

120x^2-1x=0

a = 120; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·120·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*120}=\frac{0}{240}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*120}=\frac{2}{240}
=1/120
$