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2/5x+5x=6
We move all terms to the left:
2/5x+5x-(6)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
5x+2/5x-6=0
We multiply all the terms by the denominator
5x*5x-6*5x+2=0
Wy multiply elements
25x^2-30x+2=0
a = 25; b = -30; c = +2;
Δ = b2-4ac
Δ = -302-4·25·2
Δ = 700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{700}=\sqrt{100*7}=\sqrt{100}*\sqrt{7}=10\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10\sqrt{7}}{2*25}=\frac{30-10\sqrt{7}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10\sqrt{7}}{2*25}=\frac{30+10\sqrt{7}}{50} $
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