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2/5x+6=4x-3
We move all terms to the left:
2/5x+6-(4x-3)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
2/5x-4x+3+6=0
We multiply all the terms by the denominator
-4x*5x+3*5x+6*5x+2=0
Wy multiply elements
-20x^2+15x+30x+2=0
We add all the numbers together, and all the variables
-20x^2+45x+2=0
a = -20; b = 45; c = +2;
Δ = b2-4ac
Δ = 452-4·(-20)·2
Δ = 2185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2185}}{2*-20}=\frac{-45-\sqrt{2185}}{-40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2185}}{2*-20}=\frac{-45+\sqrt{2185}}{-40} $
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