2/5x+8=2/3x

Solution for 2/5x+8=2/3x equation:

2/5x+8=2/3x

We move all terms to the left:

2/5x+8-(2/3x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2/5x-(+2/3x)+8=0

We get rid of parentheses

2/5x-2/3x+8=0

We calculate fractions


6x/15x^2+(-10x)/15x^2+8=0

We multiply all the terms by the denominator


6x+(-10x)+8*15x^2=0

Wy multiply elements

120x^2+6x+(-10x)=0

We get rid of parentheses

120x^2+6x-10x=0

We add all the numbers together, and all the variables

120x^2-4x=0

a = 120; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·120·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*120}=\frac{0}{240}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*120}=\frac{8}{240}
=1/30
$