2/5x-1/2(x+2)=7

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Solution for 2/5x-1/2(x+2)=7 equation: 



2/5x-1/2(x+2)=7

We move all terms to the left:

2/5x-1/2(x+2)-(7)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 2(x+2)!=0

x∈R



We calculate fractions


(4xx/(10x^2x+(-5x)/(10x^2x-7=0

We can not solve this equation

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