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2/5x-1/3=2+1/3x
We move all terms to the left:
2/5x-1/3-(2+1/3x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/5x-(1/3x+2)-1/3=0
We get rid of parentheses
2/5x-1/3x-2-1/3=0
We calculate fractions
54x/135x^2+(-5x)/135x^2+(-5x)/135x^2-2=0
We multiply all the terms by the denominator
54x+(-5x)+(-5x)-2*135x^2=0
Wy multiply elements
-270x^2+54x+(-5x)+(-5x)=0
We get rid of parentheses
-270x^2+54x-5x-5x=0
We add all the numbers together, and all the variables
-270x^2+44x=0
a = -270; b = 44; c = 0;
Δ = b2-4ac
Δ = 442-4·(-270)·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-44}{2*-270}=\frac{-88}{-540} =22/135 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+44}{2*-270}=\frac{0}{-540} =0 $
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