2/5x-10=32

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Solution for 2/5x-10=32 equation: 



2/5x-10=32

We move all terms to the left:

2/5x-10-(32)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We add all the numbers together, and all the variables

2/5x-42=0

We multiply all the terms by the denominator


-42*5x+2=0

Wy multiply elements

-210x+2=0

We move all terms containing x to the left, all other terms to the right

-210x=-2

x=-2/-210

x=1/105

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