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2/5x-1=9x=
We move all terms to the left:
2/5x-1-(9x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-9x+2/5x-1=0
We multiply all the terms by the denominator
-9x*5x-1*5x+2=0
Wy multiply elements
-45x^2-5x+2=0
a = -45; b = -5; c = +2;
Δ = b2-4ac
Δ = -52-4·(-45)·2
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{385}}{2*-45}=\frac{5-\sqrt{385}}{-90} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{385}}{2*-45}=\frac{5+\sqrt{385}}{-90} $
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