If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/5x-2+3(x-11)=50
We move all terms to the left:
2/5x-2+3(x-11)-(50)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/5x+3(x-11)-52=0
We multiply parentheses
2/5x+3x-33-52=0
We multiply all the terms by the denominator
3x*5x-33*5x-52*5x+2=0
Wy multiply elements
15x^2-165x-260x+2=0
We add all the numbers together, and all the variables
15x^2-425x+2=0
a = 15; b = -425; c = +2;
Δ = b2-4ac
Δ = -4252-4·15·2
Δ = 180505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-425)-\sqrt{180505}}{2*15}=\frac{425-\sqrt{180505}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-425)+\sqrt{180505}}{2*15}=\frac{425+\sqrt{180505}}{30} $
| 2-n+5=2n-7 | | -6=3/5y | | 4(t-2)+4=(2t-4 | | 180=-8x-20 | | 2-n*5=2n+4 | | 3(3.99+a)=11a | | 3z+-8=-35-6z | | 8−4(q+2)=−7 | | 20x-8x=-24 | | 2x-4=24+16x | | +2f=12f+3f-100 | | 2x-(5+9×)=16 | | 3x-24+2x+4x+11-180=180 | | 2(7x+4)=9x-4 | | 7×7×w=220.5 | | 112=6.5x-5 | | 5+6e+8e+3=8e+2-1 | | -37/12=x | | 6x+12/2=18 | | 4(−4x+2)+2x+5=4(−4x+2)+2x+5=−57 | | -4/9d=1/8+9/8+7/8 | | 5(x-3)+2=2 | | (2x+1)(2x+1)+38=180 | | 29+15x=-x−3 | | 4(−4x+2)+2x+5=4(−4x+2)+2x+5= −57−57 | | 14y-8y=22 | | -7j=3-6j | | _5(3_4x=_6+20x_9 | | 3(2=x)-4x=x+16 | | -5+n/3=15 | | x/3=238 | | a+3/1/4=5/2/9 |