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x in (-oo:+oo)
(2/5)*x-((2/5)*(x-3)) = 3 // - 3
(2/5)*x-((2/5)*(x-3))-3 = 0
(-2/5)*(x-3)+(2/5)*x-3 = 0
(2*x)/5-2/5*(x-3)-3 = 0
(-2/5*5*(x-3))/5+(2*x)/5+(-3*5)/5 = 0
2*x-2/5*5*(x-3)-3*5 = 0
6-15 = 0
-9 = 0
-9/5 = 0
-9/5 = 0 // * 5
-9 = 0
-9 = 0
x belongs to the empty set
x belongs to the empty set
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