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2/5x-3=2x-11
We move all terms to the left:
2/5x-3-(2x-11)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
2/5x-2x+11-3=0
We multiply all the terms by the denominator
-2x*5x+11*5x-3*5x+2=0
Wy multiply elements
-10x^2+55x-15x+2=0
We add all the numbers together, and all the variables
-10x^2+40x+2=0
a = -10; b = 40; c = +2;
Δ = b2-4ac
Δ = 402-4·(-10)·2
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{105}}{2*-10}=\frac{-40-4\sqrt{105}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{105}}{2*-10}=\frac{-40+4\sqrt{105}}{-20} $
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