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2/5x-3=3-2(4x-3)
We move all terms to the left:
2/5x-3-(3-2(4x-3))=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
-((3-2(4x-3)))*5x-3*5x+2=0
Wy multiply elements
-((3-2(4x-3)))*5x-15x+2=0
We add all the numbers together, and all the variables
-15x-((3-2(4x-3)))*5x+2=0
We move all terms containing x to the left, all other terms to the right
-15x-((3-2(4x-3)))*5x=-2
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