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2/5x-4=3
We move all terms to the left:
2/5x-4-(3)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/5x-7=0
We multiply all the terms by the denominator
-7*5x+2=0
Wy multiply elements
-35x+2=0
We move all terms containing x to the left, all other terms to the right
-35x=-2
x=-2/-35
x=2/35
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