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2/5x-5/3x=1/15
We move all terms to the left:
2/5x-5/3x-(1/15)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2/5x-5/3x-(+1/15)=0
We get rid of parentheses
2/5x-5/3x-1/15=0
We calculate fractions
(-45x^2)/225x^2+90x/225x^2+(-375x)/225x^2=0
We multiply all the terms by the denominator
(-45x^2)+90x+(-375x)=0
We get rid of parentheses
-45x^2+90x-375x=0
We add all the numbers together, and all the variables
-45x^2-285x=0
a = -45; b = -285; c = 0;
Δ = b2-4ac
Δ = -2852-4·(-45)·0
Δ = 81225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81225}=285$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-285)-285}{2*-45}=\frac{0}{-90} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-285)+285}{2*-45}=\frac{570}{-90} =-6+1/3 $
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