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2/5x-5/7x=x-1
We move all terms to the left:
2/5x-5/7x-(x-1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 7x!=0We get rid of parentheses
x!=0/7
x!=0
x∈R
2/5x-5/7x-x+1=0
We calculate fractions
-x+14x/35x^2+(-25x)/35x^2+1=0
We add all the numbers together, and all the variables
-1x+14x/35x^2+(-25x)/35x^2+1=0
We multiply all the terms by the denominator
-1x*35x^2+14x+(-25x)+1*35x^2=0
We add all the numbers together, and all the variables
14x-1x*35x^2+(-25x)+1*35x^2=0
Wy multiply elements
-35x^3+35x^2+14x+(-25x)=0
We get rid of parentheses
-35x^3+35x^2+14x-25x=0
We do not support expression: x^3
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