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2/5x-5=1/5(7x+10)
We move all terms to the left:
2/5x-5-(1/5(7x+10))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5(7x+10))!=0We calculate fractions
x∈R
(10x7/(25x^27+(-(1*5x)/(25x^27-5=0
We do not support expression: x^27
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