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2/5x-5x+12=-x1/5
We move all terms to the left:
2/5x-5x+12-(-x1/5)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-5x+2/5x-(-x1/5)+12=0
We get rid of parentheses
-5x+2/5x+x1/5+12=0
We calculate fractions
-5x+12=0
We move all terms containing x to the left, all other terms to the right
-5x=-12
x=-12/-5
x=2+2/5
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