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2/5x-5x+12=x+1/5
We move all terms to the left:
2/5x-5x+12-(x+1/5)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/5x-5x-(+x+1/5)+12=0
We add all the numbers together, and all the variables
-5x+2/5x-(+x+1/5)+12=0
We get rid of parentheses
-5x+2/5x-x+12-1/5=0
We calculate fractions
-5x-x+12=0
We add all the numbers together, and all the variables
-6x+12=0
We move all terms containing x to the left, all other terms to the right
-6x=-12
x=-12/-6
x=+2
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