2/5x-6=4/10x+8

Solution for 2/5x-6=4/10x+8 equation:

2/5x-6=4/10x+8

We move all terms to the left:

2/5x-6-(4/10x+8)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x+8)!=0

x∈R


We get rid of parentheses

2/5x-4/10x-8-6=0

We calculate fractions


20x/50x^2+(-20x)/50x^2-8-6=0

We add all the numbers together, and all the variables

20x/50x^2+(-20x)/50x^2-14=0

We multiply all the terms by the denominator


20x+(-20x)-14*50x^2=0

Wy multiply elements

-700x^2+20x+(-20x)=0

We get rid of parentheses

-700x^2+20x-20x=0

We add all the numbers together, and all the variables

-700x^2=0

a = -700; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-700)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-1400}=0$