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2/5x-7=1.3x-6
We move all terms to the left:
2/5x-7-(1.3x-6)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
2/5x-1.3x+6-7=0
We multiply all the terms by the denominator
-(1.3x)*5x+6*5x-7*5x+2=0
We add all the numbers together, and all the variables
-(+1.3x)*5x+6*5x-7*5x+2=0
We multiply parentheses
-5x^2+6*5x-7*5x+2=0
Wy multiply elements
-5x^2+30x-35x+2=0
We add all the numbers together, and all the variables
-5x^2-5x+2=0
a = -5; b = -5; c = +2;
Δ = b2-4ac
Δ = -52-4·(-5)·2
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{65}}{2*-5}=\frac{5-\sqrt{65}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{65}}{2*-5}=\frac{5+\sqrt{65}}{-10} $
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