If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/5x-7=12/5x^2x+3
We move all terms to the left:
2/5x-7-(12/5x^2x+3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x^2x+3)!=0We get rid of parentheses
x∈R
2/5x-12/5x^2x-3-7=0
We calculate fractions
We do not support expression: x^3
| 4x-7(1+5x)=148 | | Y=1,000x | | 10+2y=5 | | y/6+4=-12 | | -9-3r=r-1 | | 12(x+24)=18 | | 16—r/7=21 | | -6(2-7x)=408 | | 14=n−3 | | 5X-20=8x-1 | | 36=3(u-3)-8u | | k-2=10-k | | -9=w/3-6 | | 16-u=259 | | (d)=41+d | | 24=7r+r | | 22-x/8=x/3 | | 7u=27-2u | | 7x-8=5x+22 | | H(x)=2x-5 | | 14t-28=+7t+42 | | 10y+4=6y+12 | | a+120=4a | | -2(8m+8m)=-16 | | 19.5-14.7=-18.9-19.5c | | 14y=64+6y | | n+11-11n=-10n+14 | | 19.5-14.7c=-18.9-19.5 | | 8=-64z | | 14t-28=+24 | | M1=(14x+7) | | 12(x)=3 |