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2/5x=-2(x-7)
We move all terms to the left:
2/5x-(-2(x-7))=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
-((-2(x-7)))*5x+2=0
We move all terms containing x to the left, all other terms to the right
-((-2(x-7)))*5x=-2
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