If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/5y+4/5=3y/10
We move all terms to the left:
2/5y+4/5-(3y/10)=0
Domain of the equation: 5y!=0We add all the numbers together, and all the variables
y!=0/5
y!=0
y∈R
2/5y-(+3y/10)+4/5=0
We get rid of parentheses
2/5y-3y/10+4/5=0
We calculate fractions
There is no solution for this equation
| Hx3=12 | | 3x+17/2=53 | | 3x+17/2=51 | | 3x+17/2=50 | | 3x+17/2=54 | | 6=2q+2 | | 2x+23=21 | | 3x+17/2=55 | | 10-3x=-7x | | 3x+17/2=52 | | 10(x+15)+3x=39 | | 8•x-3+7=2x•4-17 | | 60+8x=108 | | g6+6=5 | | -15+2n=1 | | 3-2x=21# | | 15p+3(p-1)=8 | | 13+x+8=8+x+13 | | a+20=2a+10=180 | | 5(0.5x+2)=(4x-2) | | 19c+20=1 | | 5x-2=12=2x | | 5x−3/2=3x+8 | | 5x−32=3x+8 | | 4b+5=1(5b | | 5c+16.5=13.5=13.5+10c | | 3x+26=x+25 | | 12-7*x=16 | | (x+5)+3x+x=180 | | -15=3a+1-7 | | 28-4x=7(-2x-6) | | 4(x+3)=6(x+2) |