2/5y+y=7

Solution for 2/5y+y=7 equation:

2/5y+y=7

We move all terms to the left:

2/5y+y-(7)=0


Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R


We add all the numbers together, and all the variables

y+2/5y-7=0

We multiply all the terms by the denominator


y*5y-7*5y+2=0

Wy multiply elements

5y^2-35y+2=0

a = 5; b = -35; c = +2;
Δ = b2-4ac
Δ = -352-4·5·2
Δ = 1185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1185}}{2*5}=\frac{35-\sqrt{1185}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1185}}{2*5}=\frac{35+\sqrt{1185}}{10}
$