2/5z+4=13

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Solution for 2/5z+4=13 equation: 



2/5z+4=13

We move all terms to the left:

2/5z+4-(13)=0



Domain of the equation: 5z!=0

z!=0/5

z!=0

z∈R



We add all the numbers together, and all the variables

2/5z-9=0

We multiply all the terms by the denominator


-9*5z+2=0

Wy multiply elements

-45z+2=0

We move all terms containing z to the left, all other terms to the right

-45z=-2

z=-2/-45

z=2/45

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