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2/6x=6/5x+2
We move all terms to the left:
2/6x-(6/5x+2)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 5x+2)!=0We get rid of parentheses
x∈R
2/6x-6/5x-2=0
We calculate fractions
10x/30x^2+(-36x)/30x^2-2=0
We multiply all the terms by the denominator
10x+(-36x)-2*30x^2=0
Wy multiply elements
-60x^2+10x+(-36x)=0
We get rid of parentheses
-60x^2+10x-36x=0
We add all the numbers together, and all the variables
-60x^2-26x=0
a = -60; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·(-60)·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*-60}=\frac{0}{-120} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*-60}=\frac{52}{-120} =-13/30 $
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