2/7(5+4x)=16

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Solution for 2/7(5+4x)=16 equation: 



2/7(5+4x)=16

We move all terms to the left:

2/7(5+4x)-(16)=0



Domain of the equation: 7(5+4x)!=0

x∈R



We add all the numbers together, and all the variables

2/7(4x+5)-16=0

We multiply all the terms by the denominator


-16*7(4x+5)+2=0

Wy multiply elements

-112x(4+2=0

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