2/7(5+4x)=16

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Solution for 2/7(5+4x)=16 equation:



2/7(5+4x)=16
We move all terms to the left:
2/7(5+4x)-(16)=0
Domain of the equation: 7(5+4x)!=0
x∈R
We add all the numbers together, and all the variables
2/7(4x+5)-16=0
We multiply all the terms by the denominator
-16*7(4x+5)+2=0
Wy multiply elements
-112x(4+2=0

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