2/7(n-3)=28

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Solution for 2/7(n-3)=28 equation:



2/7(n-3)=28
We move all terms to the left:
2/7(n-3)-(28)=0
Domain of the equation: 7(n-3)!=0
n∈R
We multiply all the terms by the denominator
-28*7(n-3)+2=0
Wy multiply elements
-196n(n+2=0

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