2/7(x+1)=1/28(x+5)

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Solution for 2/7(x+1)=1/28(x+5) equation: 



2/7(x+1)=1/28(x+5)

We move all terms to the left:

2/7(x+1)-(1/28(x+5))=0



Domain of the equation: 7(x+1)!=0

x∈R





Domain of the equation: 28(x+5))!=0

x∈R



We calculate fractions


(56xx/(7(x+1)*28(x+5)))+(-7xx/(7(x+1)*28(x+5)))=0



We calculate terms in parentheses: +(56xx/(7(x+1)*28(x+5))), so:

56xx/(7(x+1)*28(x+5))

We multiply all the terms by the denominator


56xx

Back to the equation:

+(56xx)





We calculate terms in parentheses: +(-7xx/(7(x+1)*28(x+5))), so:

-7xx/(7(x+1)*28(x+5))

We multiply all the terms by the denominator


-7xx

Back to the equation:

+(-7xx)



We get rid of parentheses

56xx-7xx=0

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