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2/7(x-5)=-2+2/5x
We move all terms to the left:
2/7(x-5)-(-2+2/5x)=0
Domain of the equation: 7(x-5)!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/7(x-5)-(2/5x-2)=0
We get rid of parentheses
2/7(x-5)-2/5x+2=0
We calculate fractions
10x/(35x^2-175x)+(-14xx/(35x^2-175x)+2=0
We calculate fractions
We do not support expression: x^3
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