2/7*A=B*(3/10)*(4/9)

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Solution for 2/7*A=B*(3/10)*(4/9) equation: 


x in (-oo:+oo)

(2/7)*A = (3/10)*(4/9)*B // - (3/10)*(4/9)*B

(2/7)*A-((3/10)*(4/9)*B) = 0

(2/7)*A+(-2/15)*B = 0

2/7*A-2/15*B = 0

x należy do R

x in (-oo:+oo)

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