2/7=x-4/x+3

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Solution for 2/7=x-4/x+3 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/7 = x-(4/x)+3 // - x-(4/x)+3

4/x-x+2/7-3 = 0

4*x^-1-1*x^1-19/7*x^0 = 0

(4*x^0-1*x^2-19/7*x^1)/(x^1) = 0 // * x^2

x^1*(4*x^0-1*x^2-19/7*x^1) = 0

x^1

(-19/7)*x-x^2+4 = 0

(-19/7)*x-x^2+4 = 0

DELTA = (-19/7)^2-(-1*4*4)

DELTA = 1145/49

DELTA > 0

x = ((1145/49)^(1/2)-(-19/7))/(-1*2) or x = (-(-19/7)-(1145/49)^(1/2))/(-1*2)

x = ((1145/49)^(1/2)+19/7)/(-2) or x = (19/7-(1145/49)^(1/2))/(-2)

x in { ((1145/49)^(1/2)+19/7)/(-2), (19/7-(1145/49)^(1/2))/(-2)}

x in { ((1145/49)^(1/2)+19/7)/(-2), (19/7-(1145/49)^(1/2))/(-2) }

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