2/7b-3/8=(-19/8)

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Solution for 2/7b-3/8=(-19/8) equation: 



2/7b-3/8=(-19/8)

We move all terms to the left:

2/7b-3/8-((-19/8))=0



Domain of the equation: 7b!=0

b!=0/7

b!=0

b∈R



We calculate fractions


()/3584b^2+(-21b)/3584b^2+(-((-19*7b)/3584b^2=0

We multiply all the terms by the denominator


(-21b)+(-((-19*7b)+()=0



We calculate terms in parentheses: +(-((-19*7b)+(), so:

-((-19*7b)+(



We get rid of parentheses

-21b+(-((-19*7b)+()=0



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