2/7c=10c=

Solution for 2/7c=10c= equation:

2/7c=10c=

We move all terms to the left:

2/7c-(10c)=0


Domain of the equation: 7c!=0

c!=0/7

c!=0

c∈R


We add all the numbers together, and all the variables

-10c+2/7c=0

We multiply all the terms by the denominator


-10c*7c+2=0

Wy multiply elements

-70c^2+2=0

a = -70; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-70)·2
Δ = 560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{560}=\sqrt{16*35}=\sqrt{16}*\sqrt{35}=4\sqrt{35}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{35}}{2*-70}=\frac{0-4\sqrt{35}}{-140}
=-\frac{4\sqrt{35}}{-140}
=-\frac{\sqrt{35}}{-35}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{35}}{2*-70}=\frac{0+4\sqrt{35}}{-140}
=\frac{4\sqrt{35}}{-140}
=\frac{\sqrt{35}}{-35}
$