If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/7k+4=2/7k+13
We move all terms to the left:
2/7k+4-(2/7k+13)=0
Domain of the equation: 7k!=0
k!=0/7
k!=0
k∈R
Domain of the equation: 7k+13)!=0We get rid of parentheses
k∈R
2/7k-2/7k-13+4=0
We multiply all the terms by the denominator
-13*7k+4*7k+2-2=0
We add all the numbers together, and all the variables
-13*7k+4*7k=0
Wy multiply elements
-91k+28k=0
We add all the numbers together, and all the variables
-63k=0
k=0/-63
k=0
Równanie nie ma rozwiązania
| 3z/7-1=-6 | | 2x2-7=14-11x | | x+16-2x=15 | | 4x=49/24 | | x+18-3x=20 | | 14x-10-6x+2=0 | | 4x=146/48 | | 4x=32/48 | | 4x=34/48 | | 6x^2+11*(1-x)^2+2x(1-x)*8.12403840464*0.17=5.5 | | -0.6y+10.3=0 | | x+2/3x=29,3 | | 6x-4x-2=0 | | 8y@=16 | | 3z+6=-2 | | 2x/3=8÷4 | | x+4+x+6=-24 | | X+x+6=-24 | | 1/2(x+8)+x=1/3x+3 | | 160=40x²+240x+200 | | (6x+10)^2=-11 | | 3(24-18)+10=y | | 8m=2m30 | | 8m=2m-30 | | /1.7t=8.5/ | | 17+19y=-7 | | 120(t)=1/2t+3 | | 120(t)=1/2+3 | | 6x-7=3x+103 | | F(x)=(3x^2×x+2)(x) | | ((x+3)/2)+((5(7x+9))/3)=((3(4x+3))/12)-(7/2) | | 9x+-6=27 |