2/7k+7-8/k+5

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Solution for 2/7k+7-8/k+5 equation:


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

(2/7)*k-(8/k)+5+7 = 0

(2/7)*k-8*k^-1+5+7 = 0

2/7*k^1-8*k^-1+12*k^0 = 0

(2/7*k^2+12*k^1-8*k^0)/(k^1) = 0 // * k^2

k^1*(2/7*k^2+12*k^1-8*k^0) = 0

k^1

(2/7)*k^2+12*k-8 = 0

(2/7)*k^2+12*k-8 = 0

DELTA = 12^2-(-8*4*(2/7))

DELTA = 1072/7

DELTA > 0

k = ((1072/7)^(1/2)-12)/(2*(2/7)) or k = (-(1072/7)^(1/2)-12)/(2*(2/7))

k = 7/4*((1072/7)^(1/2)-12) or k = -7/4*((1072/7)^(1/2)+12)

k in { -7/4*((1072/7)^(1/2)+12), 7/4*((1072/7)^(1/2)-12)}

k in { -7/4*((1072/7)^(1/2)+12), 7/4*((1072/7)^(1/2)-12) }

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