2/7m+4=15

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Solution for 2/7m+4=15 equation: 



2/7m+4=15

We move all terms to the left:

2/7m+4-(15)=0



Domain of the equation: 7m!=0

m!=0/7

m!=0

m∈R



We add all the numbers together, and all the variables

2/7m-11=0

We multiply all the terms by the denominator


-11*7m+2=0

Wy multiply elements

-77m+2=0

We move all terms containing m to the left, all other terms to the right

-77m=-2

m=-2/-77

m=2/77

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