2/7p-2=p+3

Solution for 2/7p-2=p+3 equation:

2/7p-2=p+3

We move all terms to the left:

2/7p-2-(p+3)=0


Domain of the equation: 7p!=0

p!=0/7

p!=0

p∈R


We get rid of parentheses

2/7p-p-3-2=0

We multiply all the terms by the denominator


-p*7p-3*7p-2*7p+2=0

Wy multiply elements

-7p^2-21p-14p+2=0

We add all the numbers together, and all the variables

-7p^2-35p+2=0

a = -7; b = -35; c = +2;
Δ = b2-4ac
Δ = -352-4·(-7)·2
Δ = 1281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1281}}{2*-7}=\frac{35-\sqrt{1281}}{-14}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1281}}{2*-7}=\frac{35+\sqrt{1281}}{-14}
$